The height of the rhombus drawn from the top of the obtuse angle bisects the side of the rhombus.

The height of the rhombus drawn from the top of the obtuse angle bisects the side of the rhombus. Determine the corners of the diamond.

Let’s draw the diagonal BD of the rhombus.

In triangle ABD, by condition, the height BH divides the side AD in half, AH = DH, then BH is not only the height, but also the median of the triangle, and therefore AB = BK.

In a rhombus, all sides are equal, then AB = AD, and therefore AB = AD = BH, and triangle ABН is equilateral. Then the angle BAD = ABD = ADB = 60.

The diagonals of the rhombus divide the angle at the apex in half, then the angle ABC = 2 * ABD = 2 * 60 = 120.

Answer: The angles of the rhombus are 60 and 120.