The height of the tower is 533m. If the atmospheric pressure at the Earth’s surface is 760 mm Hg

The height of the tower is 533m. If the atmospheric pressure at the Earth’s surface is 760 mm Hg, then at the top of the tower it will be approximately equal to

At the earth’s surface, the pressure of the atmosphere changes in accordance with the following pattern: when ascending (descending) for every 12 meters, the pressure decreases (increases) by 1 mm of mercury. It is known from the problem statement that the atmospheric pressure near the Earth’s surface is 760 mm Hg. Art., and the height of the Ostankino TV tower, at the top of which it is necessary to determine the pressure, is 533 m.Let us find out how many times a 12 m segment will be located along the tower: 533 m: 12 m ≈ 44, which means that the pressure will drop by this value, that is: 760 mmHg Art. – 44 mm Hg. Art. ≈ 716 mmHg Art.
Answer: at the top of the tower, the pressure is approximately equal: 716 mm Hg.