The height of the water column in the glass is 5 cm. What will be the pressure of the liquid on the bottom of the glass if kerosene is poured to the same level instead of water?
To solve this problem, you first need to translate the value of the height of the water column in the glass from centimeters to meters.
Since there is 100 cm in 1 meter, we get:
5/100 = 0.05 m.
Determine the water pressure at the bottom of the glass using the following formula:
P = p * g * h,
P is the pressure;
p is the density;
g is the force of gravity;
h is the height of the post.
Substitute the known values into the formula.
P = 1000 * 9.8 * 0.05 = 490 Pa (water pressure).
Since the density of kerosene is 800 kg / m3, the pressure at the bottom of the glass will be equal to:
P = 800 * 9.8 * 0.05 = 392 Pa (kerosene pressure).
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