The height to the hypotenuse is drawn in a right-angled triangle. What angles did this height form with the legs?

The height to the hypotenuse is drawn in a right-angled triangle. What angles did this height form with the legs? if the largest of the acute angles of this triangle = 50? The angle with the smaller leg is -? The angle with a large leg is equal to -?

Since CD is the height of a right-angled triangle, triangles ACD and BCD are also right-angled.

The sum of the acute angles of a right-angled triangle is 90, then in a right-angled triangle ACD the angle ACD = (90 – CAD) = (90 – 50) = 40.

Angle АСD = 90, then angle ВСD = (90 – АСD) = 90 – 40 = 50.

Answer: The angle with the smaller leg is 40, with the larger leg 50.