The heights drawn to the sides AB and BC of an isosceles triangle ABC meet at point M.
| September 5, 2021 | education
The heights drawn to the sides AB and BC of an isosceles triangle ABC meet at point M. Line BM intersects the base of AC at point N. Define ∡ABN if ABC = 80 °.
Since, by condition, the triangle is isosceles, then the height BN, drawn from the apex of the triangle, is also its median, and the bisector of the angle ABC. Then the angle ABN = ABC / 2 = 80/2 = 40.
Answer: Angle ABN = 40.
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