The heights of the parallelogram drawn from the apex of the obtuse angle are 5
| July 17, 2021 | education
The heights of the parallelogram drawn from the apex of the obtuse angle are 5 and 2√3 and intersect at an angle of 60. Find the area of the parallelogram.
In the triangle BCK, the angle СBК = (BCН – КBН) = (90 – 60) = 300.
CosСBК = BК / ВС.
ВС = ВС / CosСВК = 2 * √3 / √3 / 2 = 4 cm.
In a parallelogram, the lengths of the opposite sides are equal, then AD = BC.
Determine the area of the parallelogram.
Savsd = AD * BH = 4 * 5 = 20 cm2.
Answer: The area of the parallelogram is 20 cm2.
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