The heights of the parallelogram drawn from the apex of the obtuse angle form an angle of 30 °.
The heights of the parallelogram drawn from the apex of the obtuse angle form an angle of 30 °. find the area of the parallelogram if its sides are 16 cm and 20 cm.
Consider a quadrangle КBНD, which, according to the condition, has an angle КBН = 30, and the angles BКD and ВНD are straight, since ВК and ВН are the heights of the parallelogram.
Then the angle КDН = АDС = 360 – 30 – 90 – 90 = 150.
Since the parallelogram has opposite angles, the angle ABC = ADC = 150.
The sum of the adjacent angles of the parallelogram is 180, then the angle BAD = 180 – ABC = 180 – 150 = 30.
Then, in a right-angled triangle AKB, the leg BK is erect against an angle of 30, and therefore is equal to half the length of the hypotenuse AB. BK = AB / 2 = 16/2 = 8 cm.
Determine the area of the parallelogram.
Savsd = AD * BK = 20 * 8 = 160 cm2.
Answer: The area of the parallelogram is 160 cm2.