The helicopter climbed vertically to a height of 2 km and flew in a horizontal direction for 20 km.
| August 6, 2021 | education
The helicopter climbed vertically to a height of 2 km and flew in a horizontal direction for 20 km. calculate the displacement and the distance traveled.
Task data: h (vertical lift of the specified helicopter) = 2 km; Sg (the path traveled by the helicopter in the horizontal direction) = 20 km.
1) Moving the specified helicopter (Pythagorean theorem): S = √ (h ^ 2 + Sg ^ 2) = √ (2 ^ 2 + 20 ^ 2) = 20.1 km.
2) The path covered by the helicopter: L = h + Sg = 2 + 20 = 22 km.
Answer: The movement of the specified helicopter is 20.1 km; the path is 22 km.
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