The high-speed elevator of the Eiffel Tower moves with an acceleration of 0.5 m / s2. What will be the weight

The high-speed elevator of the Eiffel Tower moves with an acceleration of 0.5 m / s2. What will be the weight of a tourist weighing 60 kg when descending from the tower?

Initial data: a (the acceleration with which the high-speed elevator of the Eiffel Tower moves) = 0.5 m / s2; m (tourist’s weight) = 60 kg.

Reference data: g (acceleration due to gravity) = 9.8 m / s2.

The weight of a tourist when descending on a high-speed elevator of the Eiffel Tower can be determined by the formula: P = m * (g – a).

Calculation: P = 60 * (9.8 – 0.5) = 558 N.

Answer: When descending from the Eiffel Tower, the weight of the tourist will be 558 N.