The hoist lifts 60 tons of concrete to a height of 12 meters in 1 hour. Determine the engine power

The hoist lifts 60 tons of concrete to a height of 12 meters in 1 hour. Determine the engine power needed to complete this work.

Initial data: t (duration of the lift) = 1 hour (3600 s); m (weight of the raised concrete) = 60 t (60 * 10 ^ 3 kg); h (the height to which the concrete was lifted) = 12 m.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2.

The power of the hoist motor can be calculated using the formula: N = A / t = m * g * h / t.

Calculation: N = 60 * 10 ^ 3 * 10 * 12/3600 = 2000 W (2 kW).

Answer: To perform the specified work, the lift must have an engine power of 2 kW.



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