The horizontal arm shoulders are 30 cm and 40 cm. The lesser of the two vertical forces acting

| January 19, 2021 | education

The horizontal arm shoulders are 30 cm and 40 cm. The lesser of the two vertical forces acting on the arm is 5 N. What is the second force if the arm is in equilibrium?

L1 = 30cm = 0.3m.

L2 = 40 cm = 0.4 m.

F2 = 5 N.

F1 -?

When the horizontal arm is in equilibrium, the moments of forces that act from opposite sides are equal to each other: M1 = M2.

The moment of force M is called the product of the applied force F to the smallest distance from the application of force in the axis of rotation of the lever L: M = F * L.

F1 * L1 = F2 * L2.

It can be seen from the formula that the smaller force F2 is applied to the larger lever L2.

F1 = F2 * L2 / L1.

F1 = 5 N * 0.4 m / 0.3 m = 6.7 N.

Answer: For balance, a force F1 = 6.7 N is applied to the larger arm of the horizontal lever.



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