The horse evenly pulls the cart at a speed of 0.8 m | s applying a force of 400 N. What work is done in this case in 2 hours?

We express the work of the horse to move the cart by the formula:
A = F * S, where F is a constant acting force for 2 hours, S is the movement of the horse (cart).
S = V * t, where V is the speed of the horse (cart), V = 0.8 m / s; t is the time of movement of the horse (cart), t = 2 h = 2 * 60 * 60 = 7200 s.
Let’s calculate the value of the work:
A = F * S = F * V * t = 400 * 0.8 * 7200 = 2304000 J = 2.304 * 10 ^ 6 J = 2.304 MJ.
Answer. By moving the cart for 2 hours, the horse performs work at 2.304 MJ.