The hostess cuts the cabbage by pressing the knife with a force of 50 N. The length of the knife is 12 cm, the thickness of the cutting edge is 0.2 mm. How much pressure does the knife blade put on the cabbage?
These tasks: F (the force of pressing the hostess on the knife) = 50 N; l (knife length) = 12 cm (in SI l = 0.12 m); h (thickness of the incisal edge) = 0.2 mm (in SI s = 0.2 * 10-3 m).
The pressure that the knife blade will exert on the cabbage is determined by the formula: P = F / S = F / (l * h).
Let’s make a calculation: P = 50 / (0.12 * 0.2 * 10 ^ -3) = 2083333.3 (3) Pa ≈ 2.08 MPa.
Answer: The blade of the knife will exert a pressure of 2.08 MPa on the cabbage.
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