The house is on the edge of the field. From the balcony, from a height of 5 m, the boy threw a pebble

The house is on the edge of the field. From the balcony, from a height of 5 m, the boy threw a pebble in a horizontal direction. The initial velocity of the pebble is 7 m / s. its mass is 0.1 kg in 2 seconds after the throw, the kinetic energy of the pebble is approximately equal to ..?

The stone will fly horizontally at a given speed and simultaneously fall down. Find how much the stone will fall in 2 seconds

h = g * t² / 2 = 9.8 * 4/2 = 19.6 m.

The initial height is only 7 meters, which means the stone will be on the ground in less than 2 seconds and will be motionless

v = 0.

Then the kinetic energy

E = m * v² / 2 = 0.1 * 0/2 = 0.

Answer: the kinetic energy of the stone will be 0 J.