The human body, when sweat evaporates under normal conditions, consumes 100 kJ of energy per hour.

The human body, when sweat evaporates under normal conditions, consumes 100 kJ of energy per hour. How much sweat is released in this case, if we consider the specific heat of vaporization equal to 2400 kJ / kg?

Q = 100 kJ = 100 * 10 ^ 3 J.

t = 1 h.

λ = 2400 kJ / kg = 2400 * 10 ^ 3 J / kg.

m -?

The amount of heat Q, which is necessary to transfer a substance from a liquid state of aggregation to a gaseous state, is determined by the formula: Q = λ * m, where λ is the specific heat of vaporization of a substance, m is the mass of a substance that has evaporated.

The mass of the evaporated sweat m will be determined by the formula: m = Q / λ.

m = 100 * 10 ^ 3 J / 2400 * 10 ^ 3 J / kg = 0.0416 kg.

Answer: for 1 hour, the human body secretes m = 0.0416 kg of sweat.