The hunter shoots from the gun. Determine the recoil force, if the mass of the shot is 35 g

The hunter shoots from the gun. Determine the recoil force, if the mass of the shot is 35 g, the initial velocity of the shot is 320 m / s, and the shot lasts 0.05 sec.

Given:

m = 35 grams = 0.035 kilograms – the mass of the fraction;

v = 320 meters / second – initial velocity of the shot;

t = 0.05 seconds – the period of time during which the shot lasts.

It is required to determine Fotd (Newton) – the recoil force of the gun.

Let us find the acceleration that the force of the propellant gases imparts to the fraction:

a = v / t = 320 / 0.05 = 6400 meters per second squared.

Then the force of the powder gases is equal to:

F = m * a = 0.035 * 6400 = 224 Newtons.

According to Newton’s third law, this force will be equal to the recoil force:

Fotd = F = 224 Newton.

Answer: the recoil force is 224 Newtons.