The hydroelectric dam is 13 meters high and has a capacity of 3 MW. Find the volume of water falling from the dam in 1 minute.

Dam power:
P = A / t, where P is the power of the dam (P = 3 MW = 3 * 10 ^ 6 W), A is the work of water (A = F * S, where F is the applied force (F = Ft = m * g, where m is the mass of water, g is the acceleration of gravity (g = 10 m / s ^ 2)); S is the displacement (height of the dam), S = 13 m), t is the time (t = 1 min = 60 s).
P = A / t = F * S / t = m * g * S / t.
m = P * t / (g * S) = (3 * 10 ^ 6) * 60 / (10 * 13) = 1384615 kg.
Water volume:
V = m / ρ, where ρ is the density of water (ρ = 1000 kg / m ^ 3).
V = m / ρ = 1384615/1000 ≈ 1384.6 m ^ 3.
Answer: The volume of water is 1384.6 m ^ 3.