The hydrogen density of a substance with a mass composition of 54.55% carbon, 9.09% hydrogen

The hydrogen density of a substance with a mass composition of 54.55% carbon, 9.09% hydrogen, 36.36% oxygen is 22. It easily reduces silver (I) oxide. Determine the molecular formula of this substance.

Let’s execute the solution:
1. Organic matter of composition: CxHyOz.
2. Refers to aldehydes, as it enters into a “silver mirror” reaction. General formula of aldehydes:
CnH2n + 1COH.
3. Let’s calculate the molar mass: M (CxHyOz) = M (H2) * D (H2) = 2 * 22 = 44 g / mol.
4. Determine the amount of moles of carbon, hydrogen, oxygen:
Y (C) = 54.55 / 12 = 4.5;
Y (H) = 9.09 / 1 = 9.09;
Y (O) = 36.36 / 16 = 2.27.
5. Ratio: X: Y: Z = C: H: O = 4.5: 9, 09: 2.27 = 2: 4: 1;
6. Molecular formula: C2H4O (ethanal);
7. С2Н4О + Ag2O = 2Ag + CH3COOH- reaction of oxidation of aldehyde with silver oxide, qualitative reaction to acetaldehyde, silver is released.
Answer: C2H4O-acetaldehyde.



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