The hydrogen density of the saturated monohydric alcohol is 23.

The hydrogen density of the saturated monohydric alcohol is 23. What volume of oxygen will be released during the combustion of 23 g of this alcohol?

1.Let’s find the molar mass of alcohol.

D (H2) = 23 × 2 = 46 g / mol.

C2H5OH – ethanol.

2.Let’s find the amount of substance С2H5ОH:

M (C2H5OH) = 46 g / mol.

n = 23 g: 46 g / mol = 0.5 mol.

3. Let’s find the quantitative ratios of substances.

С2H5ОH + 3O2 = 2CO2 + 3 H2O.

For 1 mol of С2H5ОH, there are 3 mol of О2.

Substances are in quantitative ratios 1: 3. The amount of O2 is 3 times more than C2H5OH.

n (О2) = 3n (С2Н5ОН) = 0.5 × 3 = 1.5 mol.

4. Find the volume of O2.

V = n Vn, where Vn is the molar volume of gas equal to 22.4 l / mol.

V = 1.5 mol × 22.4 L / mol = 33.6 L.

Answer: 33.6 liters.