The hypotenuse of a right-angled triangle is 6 cm, and one of its legs is 3√3 cm. Find the sharp corners of this triangle.

It is known that in a right-angled triangle the sine of the angle opposite to the leg is equal to the ratio of this leg to the hypotenuse. That is, 3√3 / 6 = √3 / 2 – the sine of one acute angle. Its degree measure is 60 °.

The second angle can be calculated:

– based on the fact that the sum of all the angles of the triangle is 180 °. That is, 180 ° – 60 ° = 30 °.

– by definition of the cosine of the angle – the ratio of the adjacent leg to the hypotenuse. So 3√3 / 6 = √3 / 2 is the cosine of the second acute angle. The degree measure of the second angle is 30 °.