The hypotenuse of a right-angled triangular triangle is 2m larger than one of the legs.

The hypotenuse of a right-angled triangular triangle is 2m larger than one of the legs. Find the sides of the triangle if the second leg is 4m.

Let the length of the leg AB = X meters, then the length of the hypotenuse AC = (X + 2) m.

By the Pythagorean theorem:

AC ^ 2 = AB ^ 2 + BC ^ 2.

(X +2) ^ 2 = X ^ 2 + 4 ^ 2.

X ^ 2 + 4 * X + 4 = X ^ 2 + 16.

4 * X = 12.

X = 12/4 = 3 m.

AB = 3 m.

Then AC = 3 + 2 = 5 m.

Answer: The sides of the triangle are 3, 4, 5 meters.