The ice can withstand a pressure of 8kPa. Can a car weighing 3000kg be able to walk

| February 13, 2021 | education

The ice can withstand a pressure of 8kPa. Can a car weighing 3000kg be able to walk on this ice if the surface area of its support is 800cm2

Pmax = 8 kPa = 8000 Pa.

m = 3000 kg.

g = 10 m / s2.

S = 800 cm2 = 0.08 m2.

R – ?

The pressure P is called the ratio of the force F to the area S on which this force acts. The pressure P is determined by the formula: P = F / S.

The car acts on the ice by the force of its weight F, the value of which is expressed by the formula: F = m * g, where m is the mass of the car, g is the acceleration of gravity.

The pressure of the car on the ice P will be expressed by the formula: P = m * g / S.

P = 3000 kg * 10 m / s2 / 0.08 m2 = 375000 Pa.

We see that the resulting pressure P = 375000 Pa will be greater than the maximum pressure that the ice can withstand: P> Pmax.

Answer: the car will not withstand the ice: P> Pmax.



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