The inductance of the coil is 0.04H equal to 800Hz what is the capacitance of the capacitor of this circuit

1) To apply Thompson’s formula for calculations, we find the oscillation period from the following ratio:

T = 1 / ν, where ν is the oscillation frequency of the circuit (by condition ν = 800 Hz).

T = 1/800 = 0.00125 s.

2) We calculate the capacitance of the capacitor in the circuit (C):

Т = 2 * Π * √ (L * C), where L is the inductance of the coil (by condition L = 0.04 H).

√ (L * C) = T / (2 * Π).

L * C = (T / (2 * Π)) ^ 2.

C = (T / (2 * Π)) ^ 2 / L = (0.00125 / (2 * 3.14)) ^ 2 / 0.04 = 1 * 10-6 = 1 μF.

Answer: The capacitance of the capacitor is 1 μF.