The inductance of the core coil is 22 H, the current is 10A. What EMF of self-induction occurs

The inductance of the core coil is 22 H, the current is 10A. What EMF of self-induction occurs in the coil if the circuit breaks and the current evenly drops to zero in 0.2 s?

EMF of self-induction is determined by the formula:

ε = -L * ΔI / Δt, where L is the inductance of the circuit, ΔI is the change in current strength, Δt is time.

Since the current drops to zero:

ΔI = 10 – 0 = 10 A.

Then:

ε = -22 * 10 / 0.2 = -1100 V. (the minus sign indicates the opposite direction of the induction current).

Answer: the desired EMF is equal to -1100 V.