The information volume of the text is 135 kB. the text occupies 16 pages on each page the same

The information volume of the text is 135 kB. the text occupies 16 pages on each page the same number of lines, each line contains 96 characters. the text is written in an alphabet with a capacity of 512. Determine how many lines are remembered on each page.

1. Let’s translate 135 Kbytes into bits.

in 1 KB 1024 bytes. 135 * 1024 = 138,240 bytes.

in 1 byte 8 bits. 138240 * 8 = 1105920 bits.

2. Find out how many bits each character carries. The formula for finding information is N = 2i, where N is the number of characters in the alphabet, and i is the amount of information in bits that one character carries.

512 = 29, which means one character carries 9 bits of information.

3. Let’s calculate how many characters are in the whole text.

1105920: 9 = 122880 characters.

3. Let’s count how many characters are on one page (16 pages in total).

122880: 16 = 7680 characters per page.

4. Find out how many lines are on one page, if 96 characters fit on a line.

7680: 96 = 80 lines.

Answer: 80 lines.