The information volume of the text, prepared with the help of a computer, is 5 MB. 1 character weighs 1 byte.

The information volume of the text, prepared with the help of a computer, is 5 MB. 1 character weighs 1 byte. How many characters does this text contain?

Information volume: V = K × I.
If V = 5Mb (41.943.040bit), and the information weight of each character = 1byte (8bit), then:
41.943.040 = K × 8
K = 41,943,040: 8 = 5,242,880 characters.
Answer: The text contains 5,242,880 characters.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.