The initial speed of the body is 16 m / s, the final speed is 8 m / s. Determine the distance traveled in 4s.

Since the body is moving equally slowly, the formula for the distance traveled is:
S = (V² – V0²) / 2a, where V is the final speed of the body (V = 8 m / s), V0 is the initial speed of the body (V0 = 16 m / s), and is the acceleration of the body.
Body speed:
V = V0 + a * t, where t is the time of body movement (t = 4 s).
a * t = V – V0.
a = (V – V0) / t = (8 – 16) / 4 = -8 / 4 = -2 m / s².
Let’s calculate the path traveled by the body:
S = (V² – V0²) / 2a = (8² – 16²) / 2 * (-2) = -192 / (-4) = 48 m.
Answer: The body will travel a path equal to 48 m.