The initial speed of the body is 5m / s, the speed after 3 seconds is 14m / s. What is the path covered by the body in 3s?

The initial speed of the body is 5m / s, the speed after 3 seconds is 14m / s. What is the path covered by the body in 3s? Under the influence of what force did the body move if its mass is 2kg.

V0 = 5 m / s.

t = 3 s.

V1 = 14 m / s.

m = 2 kg.

S -?

F -?

Since the body is moving uniformly, its path S will be determined by the formula: S = V0 * t + a * t2 / 2, where V0 is the initial velocity of the body, t is the time of movement, a is the acceleration of the body.

The acceleration of the body a is expressed by the formula: a = (V – V0) / t.

a = (14 m / s – 5 m / s) / 3 s = 3 m / s2.

S = 5 m / s * 3 s + 3 m / s2 * (3 s) 2/2 = 28.5 m.

We express the force by the formula: F = m * a.

F = 2 kg * 3 m / s2 = 6 N.

Answer: the body will cover the path S = 28.5 m, the force F = 6 N. acts on the body.