The initially resting electron begins to move under the action of the forces of a uniform electric field with an intensity

| November 20, 2020 | education

The initially resting electron begins to move under the action of the forces of a uniform electric field with an intensity of E = 2.0 · 10 ^ 5 V / m. What speed (in Mm / s) an electron will acquire in 1.0 ns What distance (in mm) will an electron fly during this time?

E = 2 * 10 ^ 5 V / m.
t = 1 ns = 1 * 10 ^ -9 s.
q = 1.6 * 10 ^ -19 Cl.
m = 9.1 * 10 ^ -31 kg.
V0 = 0 m / s.
V -?
S -?
The force F acts on the electron, the value of which is determined by the formula: F = q * E.
Let’s write Newton’s 2 law for an electron: F = m * a.
q * E = m * a.
Let us express the acceleration of an electron: a = q * E / m.
a = 1.6 * 10 ^ -19 C * 2 * 10 ^ 5 V / m / 9.1 * 10 ^ -31 kg = 35 * 10 ^ 15 m / s ^ 2.
Let us express the acceleration of an electron by another formula: a = (V – V0) / t. since V0 = 0 m / s, then a = V / t.
q * E / m = V / t.
V = q * E * t / m.
V = 1.6 * 10 ^ -19 C * 2 * 10 ^ 5 V / m 1 * 10 ^ -9 s / 9.1 * 10 ^ -31 kg = 35 * 10 ^ 6 m / s = 35 Mm / from.
The distance S that the electron flew is found by the formula: S = V ^ 2 / 2a.
S = (35 * 10 ^ 6 m / s) ^ 2/2 * 35 * 10 ^ 15 m / s ^ 2 = 17.5 * 10 ^ -3 m = 0.0175 m.
Answer: the speed of the electron is V = 35 Mm / s, the movement of the electron is S = 0.0175 m.



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