The inner angles of the triangle are proportional to the numbers 2,4,9. Then the larger of them is equal.

Let the value of the angle CAB = 2 * X0, then, by condition, the value of the angle ACB = 4 * X0, and the angle ABC = 9 * X0.
The sum of the inner angles of the triangle is 1800, then (2 * X + 4 * X + 9 * X) = 180.
15 * X = 180.
X = 180/15 = 120.
Then the angle CAB = 2 * 12 = 240, angle ACB = 4 * 12 = 480, angle ABC = 9 * 12 = 1080.
Answer: The largest angle of the triangle is 1080.



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