The intensity of the field of a point charge at a distance of 5 cm from the charge is equal to 400
| April 26, 2021 | education
The intensity of the field of a point charge at a distance of 5 cm from the charge is equal to 400 kV / m. What is the field strength at a point located at a distance of 10 cm?
Task data: r1 (initial distance from a point charge) = 5 cm; E1 (field strength at the initial distance) = 400 kV / m; r2 (finite distance from a point charge) = 10 cm.
The field strength at a point that is 10 cm away from the charge is determined from equality (we take into account that the strength is calculated by the formula E = k * | q | / r ^ 2): E1 * r1 ^ 2 = k * | q | = E ^ 2 * r2 ^ 2, whence E ^ 2 = E1 * r1 ^ 2 / r2 ^ 2.
Calculation: E ^ 2 = 400 * 5 ^ 2/10 ^ 2 = 100 kV / m.
Answer: The field strength will be 100 kV / m.
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