The interaction of 110 grams of sulfuric acid solution required 80 grams of 10% sodium hydroxide solution

| May 26, 2021 | education

The interaction of 110 grams of sulfuric acid solution required 80 grams of 10% sodium hydroxide solution. Calculate the mass fraction of acid in the original solution.

1. The interaction of sulfuric acid and sodium hydroxide is described by the equation:

H2SO4 + 2NaOH = Na2SO4 + 2H2O;

2. Calculate the mass of sodium hydroxide:

m (NaOH) = w (NaOH) * m (NaOH solution) = 0.1 * 80 = 8 g;

3. Find the chemical amount of hydroxide:

n (NaOH) = m (NaOH): M (NaOH);

M (NaOH) = 23 + 16 + 1 = 40 g / mol;

n (NaOH) = 8: 40 = 0.2 mol;

4. Determine the amount of acid reacted:

n (H2SO4) = n (NaOH): 2 = 0.2: 2 = 0.1 mol;

5. Let’s calculate the mass of sulfuric acid:

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

m (H2SO4) = 0.1 * 98 = 9.8 g;

6. Set the mass fraction of acid in the original solution:

w (H2SO4) = m (H2SO4): m (solution H2SO4) = 9.8: 110 = 0.0891 or 8.91%.

Answer: 8.91%.



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