The interaction of 32 g of iron (III) oxide with carbon monoxide leads to the production of 19.6 g of iron

The interaction of 32 g of iron (III) oxide with carbon monoxide leads to the production of 19.6 g of iron and the release of carbon dioxide. Calculate the practical iron yield in% of the theoretical.

Let’s write the reaction equation:
Fe2O3 + 3CO = 2Fe + 3CO2

Let’s calculate the theoretical mass of iron:
n (Fe2O3) = m (Fe2O3) / Mr (Fe2O3) = 32/160 = 0.2 mol;

n (Fe) theory = 2n (Fe2O3) = 0.2 * 2 = 0.4 mol;

m (Fe) theor = n (Fe) theor * Mr (Fe) = 0.4 * 56 = 22.4 g

Let’s calculate the iron output:
Output = m (Fe) practical / m (Fe) theory * 100% = 19.6 / 22.4 * 100% = 87.5%