The interaction of calcium weighing 20 g with chlorine formed calcium chloride weighing 52 g.

The interaction of calcium weighing 20 g with chlorine formed calcium chloride weighing 52 g. Calculate the yield of this chemical reaction.

Ca + Cl2 = CaCl2
n (Ca) = m \ M = 20 \ 40 = 0.5 mol
for ur-th p-and n (Ca) = n (CaCl2) = 0.5 mol
m theor (CaCl2) = nM = 0.5 * 111 = 55.5 g
output p-i = m (practical) \ m (theory) = 52 \ 55.5 = 0.94 (94%)
Answer: 94%



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