The interaction of chlorine and 500 liters of hydrogen produced hydrogen chloride, the volume of which was.

H2 + Cl2 = 2HCl
n (H2) = V / Vm = 500 l / 22.4 l / mol = 22.3 mol 22.3 / 1 = x / 2x = 44.6 mol
V (HCl) = Vm * n = 22.4 L / mol * 44.6 mol = 999.04 L



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