The interaction of ethanol with acetic acid weighing 3.6 g in the presence of a catalyst yielded

The interaction of ethanol with acetic acid weighing 3.6 g in the presence of a catalyst yielded ethyl acetate weighing 4.5 g. Determine the practical yield (%) of the organic reaction product.

Let’s find the amount of acid substance by the formula:

n = m: M.

M (CH3COOH) = 60 g / mol.

n = 3.6 g: 60 g / mol = 0.06 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

С2Н5ОН + CH3 – COОH → CH3 – COО – С2Н5 + H2O.

According to the reaction equation, there is 1 mol of ethyl acetate per 1 mol of acid. Substances are in quantitative ratios 1: 1.

The amount of substance will be the same.

n (CH3COOH) = n (CH3 – CO O -C2H5) = 0.06 mol.

Let’s find the mass of ethyl acetate by the formula:

m = n × M,

M (CH3 – CO O – C2H5) = 88 g / mol.

m = 0.3 mol × 88 g / mol = 26.4 g.

26.4 g were calculated (theoretical yield).

By the condition of the problem, the aldehyde was 4.5 g.

Let’s find a practical way out of the product.

26.4 g – 100%

4.5 g – x%,

x = (4.5 x 100%): 26.4 g = 17.05%.

Answer: 17.05%.