The interaction of hydrogen and oxygen formed 36 g of water. Calculate the masses of hydrogen

The interaction of hydrogen and oxygen formed 36 g of water. Calculate the masses of hydrogen and oxygen that will be required for this reaction.

Given:
m (H2O) = 36 g
To find:
m (H2)
m (O2)
Decision:
2H2 + O2 = 2H2O
n (H2O) = m / M = 36 g / 18 g / mol = 2 mol
n (H2O): n (H2) = 1: 1
n (H2) = 2 mol
n (H2O): n (O2) = 2: 1
n (O2) = 2 mol / 2 = 1 mol
m (H2) = n * M = 2 mol * 2 g / mol = 4 g
m (O2) = n * M = 1 mol * 32 g / mol = 32 g
Answer: 4 g; 32 g