The internal energy of a monatomic ideal gas taken in an amount of matter of 2 mol is equal to at a temperature of 727.
| May 24, 2021 | education
To calculate the value of the internal energy of the specified monatomic ideal gas, we apply the formula: U = i / 2 * ν * R * T.
Variables and constants: i – the number of degrees of freedom of molecules (i = 3); ν is the amount of substance of the specified gas (ν = 2 mol); R – universal gas constant (R = 8.314 J / (K * mol)); T is the temperature of the indicated gas (T = 1000 K (727 ºС)).
Calculation: U = i / 2 * ν * R * T = 3 * 2 * 8.314 * 1000/2 = 24.942 * 10 ^ 3 J ≈ 25 kJ.
Answer: 4) The value of the internal energy of 2 mol of the indicated monoatomic ideal gas is 25 kJ.
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