The internal energy of two moles of helium taken at a temperature of 27 C is …

To find the value of the internal energy of 2 mol of taken helium, we apply the formula: U = i * ν * R * T / 2.

Constants and variables: i – the number of degrees of freedom of molecules (helium is a monoatomic gas and i = 3); ν is the amount of matter taken helium (ν = 2 mol); R – universal gas constant (R = 8.314 J / (K * mol)); T is the helium temperature (Т = 300 К (27 ºС)).

Calculation: U = 0.5 * i * ν * R * T = 3 * 2 * 8.314 * 300/2 ≈ 7.5 * 10 ^ 3 J.

Answer: The value of the internal energy of 2 mol of taken helium is 7.5 kJ.