The internal resistance of the source is 2 ohms. The current in the circuit is 0.5 A.

The internal resistance of the source is 2 ohms. The current in the circuit is 0.5 A. The voltage on the outer section of the circuit is 50 V. Determine the short-circuit current.

r = 2 ohms.

I = 0.5 A.

U = 50 V.

Ikor -?

The short circuit condition is the absence of external resistance of the circuit R = 0.

According to Ohm’s law for a closed circuit, we express the current strength during a short circuit: Icor = EMF / r.

Let’s write Ohm’s law for a closed circuit: I = EMF / (R + r).

EMF = I * (R + r).

We find the external resistance of the circuit R from Ohm’s law for a section of the circuit: R = U / I.

EMF = I * (U / I + r).

The formula for determining the current strength during a short circuit will be: Icor = I * (U / I + r) / r.

Icor = 0.5 A * (50 V / 0.5 A + 2 Ohm) / 2 Ohm = 25.5 A.

Answer: with a short circuit, the current strength is Icor = 25.5 A.