The jet flew a distance of 2,700 km in 1 hour. in the opposite direction its speed was 715 m / s.

The jet flew a distance of 2,700 km in 1 hour. in the opposite direction its speed was 715 m / s. how much m / s was its initial speed high?

Note that the way there (S1) and the way back (S2) will be the same.
Let’s find the speed on the path S1:
V1 = S1 / t1 = 2700/1 = 2700 km / h = 2700000/3600 = 750 m / s
V2 = 715m / s.
Delta V = 750-715 = 35m / s
Answer: The initial speed was 35 m / s higher



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