The jet plane flies at a speed of 720 km / h. From a certain moment the plane moves with acceleration for 10

| August 7, 2021 | education

The jet plane flies at a speed of 720 km / h. From a certain moment the plane moves with acceleration for 10 seconds and in the last second it covers a distance of 295m. aircraft final speed and acceleration?

V0 = 720 km / h = 200 m / s.

t1 = 9 s.

t2 = 10 s.

S = 295 m.

V -?

a -?

The path S traversed by the body with uniformly accelerated movement is determined by the formula: S = V0 * t + a * t2 / 2.

Let us express the traversed path S1 in time t1 = 9 s: S1 = V0 * t1 + a * t12 / 2.

Let us express the traversed path S2 in time t10 = 10 s: S2 = V0 * t ^ 2 + a * t2 ^ 2/2.

The distance traveled by the plane in the tenth second S will be the difference: S = S2 – S1.

S = V0 * t ^ 2 + a * t2 ^ 2/2 – V0 * t1 – a * t1 ^ 2/2.

S = V0 * 10 + a * (10) ^ 2/2 – V0 * 9 – a * (9) ^ 2/2.

S = V0 + 9.5 * a.

a = (S – V0) / 9.5.

a = (295 – 200) / 9.5 = 10 m / s2.

V = V0 + a * t2.

V = 200 m / s + 10 m / s2 * 10 s = 1200 m / s.

Answer: the acceleration of the aircraft is a = 10 m / s2, the speed of the aircraft will be V = 1200 m / s.



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