The jet plane starts landing on the aerodrome at a speed of 576 km / h. What path will it cover while

The jet plane starts landing on the aerodrome at a speed of 576 km / h. What path will it cover while moving with acceleration a = 5m / s2.

Given
v0 = 576 km / h
v = 0 m / s
a = 5 m / s ^ 2
Find: s -?
SI 576 km / h = 160 m / s
Decision
s = v0t – (at ^ 2) / 2
t = (v – v0) / a
t = 0 – 160/5 = 32 s
s = 160 x 32 – (5×32 ^ 2) / 2 = 5120 – 2560 = 2560 m
Answer: s = 2560 m



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