The large piston of the hydraulic machine, which has an area of 60cm2, lifts a load weighing 3000H
| August 1, 2021 | education
The large piston of the hydraulic machine, which has an area of 60cm2, lifts a load weighing 3000H. Find the area of the smaller piston if a force of 200N acts on it.
These tasks: Sb (area of the larger piston of the hydraulic machine) = 60 cm2; RB (weight of the load being lifted by a large piston) = 3000 N; Fm (force acting on the smaller piston) = 200 N.
The area of the smaller piston of the hydraulic machine is determined from the equality: P = Fb / Sb = Fm / Sm, whence Sm = Fm * Sb / Fb = Fm * Sb / Rb.
Calculation: Sm = 200 * 60/3000 = 4 cm2.
Answer: The smaller piston of a hydraulic machine has an area of 4 cm2.
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