The large piston of the ram lifts a load of 40 kN when the small piston is acted upon by a force of 400 N.
| February 25, 2021 | education
The large piston of the ram lifts a load of 40 kN when the small piston is acted upon by a force of 400 N. What is the area of the large piston if the area of the small piston is 4 cm2?
To find the value of the area of the larger piston of the used lift, we apply the proportion: Fbp / Fmp = Sbp / Smp, from where we express: Sbp = Fbp * Smp / Fmp = P * g * Smp / Fmp.
Variables and constants: P – weight of the load (P = 40 kN = 4 * 10 ^ 4 N); g – acceleration due to gravity (g ≈ 10 m / s2); Smp is the area of the small piston (Smp = 4 cm2); Fmp – force on the small piston (Fmp = 400 N).
Calculation: Sbp = P * g * Smp / Fmp = 4 * 10 ^ 3 * 10 * 4/400 = 400 cm2.
Answer: The larger piston of the lifter used has an area of 400 cm2.
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