The larger base of an isosceles trapezoid is 12 cm, its lateral side is 4 cm and the angle between them is 60 degrees.
The larger base of an isosceles trapezoid is 12 cm, its lateral side is 4 cm and the angle between them is 60 degrees. Find the length of the smaller base.
Let’s build the height of the HВ trapezoid ABCD.
Triangle ABH is rectangular, in which the angle ВAН, by condition, is equal to 60, then the angle AВН = 90 – 60 = 30.
Leg AH lies opposite angle 30, then its length is equal to half the length of the hypotenuse AB.
AH = AB / 2 = 4/2 = 2 cm.
Let’s build the CM height. Since the trapezoid is isosceles, then AB = CD, angle BAН = CDM, then right-angled triangles ABH and CDM are equal in hypotenuse and acute angle. Then DМ = АН = 2 cm.
The length of the segment MH = AD – AH – DM = 12 – 2 – 2 = 8 cm.
Quadrangle BCMN is a rectangle, then BC = MH = 8 cm.
Answer: The length of the smaller base is 8 cm.