The largest number of non-metal atoms is contained in 5 A. NaCl b. K2SO4 c. H2O d. HNO3.

We calculate according to these formulas: N = n * Na n = m / M
N is the number of molecules
Na – Avogadro’s number Na = 6.022 * 10 ^ 23 mol ^ -1
n – amount of substance
m- mass
M – molar mass
n (NaCl) = 5 / 58.5 = 0.09 mol contains 1 mol of non-metal atoms => N = 0.09 * Na atoms
n (K2SO4) = 5/174 = 0.03 mol => N = 0.03 * 5 * Na = 0.15 * Na
n (H2O) = 5/18 = 0.3 mol => N = 0.3 * 3 = 0.9 * Na
n (HNO3) = 5/63 = 0.08 mol => N = 0.08 * 5 = 0.4 * Na
Answer in 5g H2O