The lateral surface of a regular quadrangular pyramid is 240 cm2, and its lateral edge is 12 cm

univerkov | February 1, 2021 | education

The lateral surface of a regular quadrangular pyramid is 240 cm2, and its lateral edge is 12 cm. Find the area of the base of the pyramid

To solve this problem, we need to perform the following actions:
Side ribs b = √ (32 / (1/2)) = 8.
Base diagonal d = 8√2.
Base side a = 8√2 * cos (45) = 8.
The side faces are equilateral triangles.
S (side) = 4 * (a² * √3) / 4 = 64√3.
As a result of the actions taken, we get the answer to the problem: 64√3.

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