The law of motion of bodies thrown vertically upward is given by the equation S = 19.6t-4.9t ^ 2.

The law of motion of bodies thrown vertically upward is given by the equation S = 19.6t-4.9t ^ 2. Find the highest body height.

General formula for describing uniformly accelerated motion: S = v0 * t + a * t² / 2,

here v0 is the initial velocity, a is the acceleration, and t is the time of movement.

Therefore, by the problem statement, we define v0 = 19.6.

The instantaneous speed at uniformly accelerated motion changes according to the law: v = v0 + a * t,

for our conditions:

v = 19.6 – 9.8 * t.

The highest lifting height of the body coincides with the moment when its instantaneous velocity becomes equal to zero, i.e.:

19.6 – 9.8 * t = 0, whence t = 2 s.

S = 19.6 * 2 – 4.9 * 2² = 19.6 m.

Answer: 19.6 m.