The leader of the bicycle race completed its first flat stage with an average speed of 12 km / h in 1.50 hours, and the second mountain stage with an average speed of 9.0 km / h in 2.5. What is the average speed of the leader’s movement at two stages?
Data: V1 (leader speed at flat stage) = 12 km / h; t1 (time of movement at the flat stage) = 1.5 hours; V2 (speed of the leader in the mountain stage) = 9 km / h; t2 (travel time during the mountain stage) = 2.5 hours.
The average speed of a leader at two stages of a bicycle race is determined by the formula: Vav. = (S1 + S2) / (t1 + t1) = (V1 * t1 + V2 * t2) / (t1 + t2).
Calculation: Vav. = (12 * 1.5 + 9 * 2.5) / (1.5 + 2.5) = 40.5 / 4 = 10.125 km / h.
Answer: The leader of the bicycle race was moving at an average speed of 10.125 km / h.
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